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One cylinder has a volume that is 8 cm^(3) less than 7/8 of the volume of a second cylinder. If the first cylinder’s volume is 216 cm^(3) , what is the correct equation and value of x, the volume of the second cylinder?

Respuesta :

[tex]\bf \begin{cases} \stackrel{\textit{volume of 1st cylinder}}{V=216}\\\\ \stackrel{\textit{volume of 2nd cylinder}}{x=\cfrac{7}{8}V-8}\\\\ x=\cfrac{7}{8}(216)-8\\\\ \qquad 189-8\\ \qquad 181 \end{cases}[/tex]
The correct answer is D) 7/8x - 8 = 216; x = 256 cm³

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