For this case we have the following expression: y = (x-5) / (x ^ 2 - 6x +5) Rewriting the expression we have: y = (x-5) / ((x-5) (x-1)) Therefore, discontinuity points are those that make the denominator zero: x = 5 x = 1 The point of removable discontinuity is: x = 5 Answer: Discontinuity: x = 5 x = 1 Removable: x = 5
