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PLEASE I BEG YOU, HELP ME!!!!!!!! Find the rate of change of the function h(x) = 2^x on the interval 2 ≤ x ≤ 4. The rate of change is what?

Respuesta :

rate of change=
[tex] \frac{y2 - y1}{x2 - x1} [/tex]
y2 and x2 being the coordinates of the point furthest from the (0,0) and x1 and y1 being the nearest

so if x1=2 then
h(x)= 2^2 = 4

and if x2=4 then
h(x)= 2^4=16

so rate of change is
[tex] \frac{16 - 4}{4 - 2} = \frac{12}{2 } = 6[/tex]

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