Old McDonald raises chickens and sheep in his farm. His livestock has a total of 55 heads and 142 legs among them (not counting the farmer!). How many chickens and how many sheep does he have?

Respuesta :

Let the number of sheep be denoted by the letter "S".

Let the number of chicken be denoted by the letter "C".

From the given information about the number of heads (headcount) it is clear that:

[tex] S+C=55 [/tex].................(Equation 1)

We know that 1 Sheep has 4 legs and 1 chicken has 2 legs. Therefore, "S" sheep will have 4S legs and "C" chickens will have 2C legs.

Therefore, from the information on legs we have:

[tex] 4S+2C=142 [/tex]

Dividing both sides by 2 we get:

[tex] 2S+C=71 [/tex].............(Equation 2)

Now, if we subtract (Equation 1) from (Equation 2) we will get:

[tex] (2S+C)-(S+C)=71-55 [/tex]

or, [tex] S=16 [/tex]

Plugging in this in (Equation 1) we get:

[tex] 16+C=55 [/tex]

or [tex] C=39 [/tex]

Thus the number of sheep is 16 and the number of chicken is 39.


If old McDonald raises chickens and sheep in his farm. His livestock has a total of 55 heads and 142 legs among them (not counting the farmer!) then they have 16 sheep and 39 chicken

What is linear equation ?

A equation of degree one is known as linear equation.

Here given that old McDonald raises chickens and sheep in his farm. His livestock has a total of 55 heads and 142 legs among them (not counting the farmer!).

Now let suppose number of sheep= x

and  number of chicken=y

We can write equation as

x+y=55  or y=55-x   ...(1)

and

4x+2y= 142  ...(2)

Now we can simplify these equations as

From equation (1) and (2)

[tex]4x+2(55-x)=142\\\\2x+55-x=71\\\\x=71-55\\\\x=16\\\\y= 55-x\\\\y=55-16\\\\y= 39\\[/tex]

If old McDonald raises chickens and sheep in his farm. His livestock has a total of 55 heads and 142 legs among them (not counting the farmer!) then they have 16 sheep and 39 chicken

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