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What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (−1, −1)?

y + 1 =
(x + 1)

Respuesta :

altavistard
First find the slope of this new line; it's the same as the slope of the "given line," which you unfortunately have not yet given.  Let's call that slope "m."

Then, the equation in point-slope form of the new line is

y - (-1) = m(x - [-1]), or    y+1 = m(x+1)

Please go back to the original question, obtain the slope of the "given line," and substitute that value for m in y+1 = m(x+1).

The equation of the line that is parallel to the given line and passes through the given point is y + 1 = 0.

What is Equation of line?

  • Algebraic representation of the locus of points to form the line.
  • The general equation is: y = mx + c (c = y-intercept; m = slope).

Given:

Equation of line is:

y + 1 = x + 1

point (x₁, y₁) = (−1, −1)

We will convert the given equation of line to y = mx + c.

⇒ y + 1 = x + 1

⇒ y = x

⇒ m (slope) = 0

Line is parallel to the given line y + 1 = x + 1.

∴ Slope of line (y + 1 = x + 1) = Slope of required line

⇒ Slope of required line (m) = 0

also we have, (x₁, y₁) = (−1, −1)

Equation of line in point-slope form is:

⇒ y - y₁ = m(x-x₁)

⇒ y - (-1) = 0 × (x +1)

⇒ y + 1 = 0

⇒ y = -1

Therefore, the required equation of line in point-slope from is y + 1 = 0.

Learn more about the Equation of Line here: https://brainly.com/question/13657035

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