The function is defined only if [tex] x+1 \geq 0 \iff x \geq -1 [/tex]. So, the leftmost point is [tex] x=-1 [/tex], and we have
[tex] f(-1)=\frac{1}{2}sqrt(-1+1) = 0 [/tex]
So, the first point is [tex] (-1,0) [/tex]
The three additional points seem arbitrary, so let's choose [tex] x=0,1,2 [/tex]. We have:
[tex] f(0)=\frac{1}{2}sqrt(0+1) = \frac{1}{2} [/tex]
So, the second point is [tex] (0,\frac{1}{2}) [/tex]
[tex] f(1)=\frac{1}{2}sqrt(1+1) = \frac{\sqrt{2}}{2} [/tex]
So, the third point is [tex] (1,\frac{\sqrt{2}}{2}) [/tex]
[tex] f(2)=\frac{1}{2}sqrt(2+1) = \frac{\sqrt{3}}{2} [/tex]
So, the fourth point is [tex] (2,\frac{\sqrt{3}}{2}) [/tex]
