Answer:
[tex]g=0.66\ m/s^2[/tex]
Explanation:
Given that,
Initial upward speed, u = 6 m/s
Maximum height of the astronaut, h = 27 m
Let g is the acceleration due to gravity on the planet. It can be calculated using the conservation of energy as :
[tex]mgh=\dfrac{1}{2}mu^2[/tex]
[tex]h=\dfrac{u^2}{2g}[/tex]
[tex]g=\dfrac{u^2}{2h}[/tex]
[tex]g=\dfrac{(6)^2}{2\times 27}[/tex]
[tex]g=0.66\ m/s^2[/tex]
So, the magnitude of the acceleration due to gravity on the planet is [tex]0.66\ m/s^2[/tex]. Hence, this is the required solution.
