The volume of oblique cone =[tex] \frac{1}{3} \pi r^{2} h [/tex]
Now radius is doubled is now it is 2r
And height is reduced to 2/3 of its original size that is 2/3 h
So plugging the values we get volume
New Volume = [tex] \frac{1}{3} \pi (2r)^2 (\frac{2}{3} h) [/tex]
= [tex] \frac{1}{3} \pi 4r^2 (\frac{2}{3} h) = \frac{8}{6} \pi r^{2} h =\frac{8}{2} (\frac{1}{3} \pi r^{2} h ) [/tex][tex] =4*(\frac{1}{3} \pi r^{2} h ) [/tex]
It means the volume becomes 4 times
