Answer: -
A 3.00-l flask is filled with gaseous ammonia, NH₃. the gas pressure measured at 26.0 ∘c is 1.55 atm . assuming ideal gas behavior, 3.23 grams of ammonia are in the flask
Explanation: -
Volume V = 3.00 L
Pressure P = 1.55 atm
Temperature T = 26.0 °C + 273 = 299 K
We know the value of Universal gas constant R = 0.082 L atm K−1
mol−1
We use the ideal gas equation
PV = nRT
Number of moles of Ammonia n = [tex] \frac{PV}{RT} [/tex]
= [tex] \frac{1.55 atm x 3.00 L}{0.082 L atm K−1 x 299 K} [/tex]
= 0.19 mol
Molar mass of NH₃ = 14 x 1 + 1 x 3 = 17 g / mol
Mass of NH₃ = Molar mass of NH₃ x number of moles of NH₃
= 17 g / mol x 0.19 mol
= 3.23 g
