Let AB = t. And since X lies in the middle, so AX=BX = t/2 .
Let the height of the smaller flagpole is AO and of larger flagpole is BP .
Using tangent ratio rule in each triangle, we will get
[tex] tan 35 =\frac{AO}{t/2} , tan 45= \frac{BP}{t/2}
//
AO = \frac{t*tan35}{2}, BP=\frac{t*tan45}{2} [/tex]
And there ratio is
[tex] \frac{AO}{BP}= \frac{tan 35}{tan 45}=\frac{0.7}{1} [/tex]