Respuesta :
Number of moles required to neutralize the solution=0.0354×0.0997
=0.0035mol
2 mol of NaOH required to neutralize 1 mol of diprotic acid.
So moles of acid 0.0035/2=0.0017
Number of moles of acid=Mass of diprotic acid/Molar mass of diprotic acid
0.0017 =0.3041/Molar mass of diprotic acid
Molar mass of diprotic acid=0.3041/0.0017
=178.8 g/mol
The molar mass of the solid acid 172.08 g/mol
To calculate the molar mass of the solid acid,
First, we will write a balanced chemical equation for the reaction
Let the diprotic acid be H₂X
The balanced chemical equation for the reaction is
H₂X + 2NaOH → Na₂X + 2H₂O
This means
1 mole of the diprotic acid is needed to completely neutralize 2 moles of NaOH
Now, we will determine the number of moles of NaOH that reacted
Using the formula
Number of moles = Concentration × Volume
From the question
Volume of NaOH = 35.45 mL = 0.03545 L
Concentration of NaOH = 0.0997 M
∴ Number of moles of NaOH = 0.0997 × 0.03545
Number of moles of NaOH = 0.003534365 moles
Now,
From the balanced chemical equation,
Since 1 mole of the diprotic acid is needed to completely neutralize 2 moles of NaOH
Then,
[tex]\frac{0.003534365}{2}[/tex] moles of the diprotic acid will be needed to completely neutralize 3.534365 moles of NaOH
[tex]\frac{0.003534365}{2}= 0.0017671825[/tex] moles
∴ 0.0017671825 moles of the diprotic acid reacted
Now, for the molar mass of the diprotic acid
From the formula
[tex]Molar\ mass = \frac{Mass}{Number\ of\ moles}[/tex]
From the question
Mass of the diprotic acid neutralized = 0.3041 g
∴ Molar mass of the acid = [tex]\frac{0.3041}{0.0017671825}[/tex]
Molar mass of the acid = 172.08 g/mol
Hence, the molar mass of the solid acid 172.08 g/mol
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