Respuesta :
[tex] y=\sqrt{x} [/tex]
As we know, the square root of negative numbers.
Hence, the x must be a positive value and greater than 0.
So, x:x∈[0,∞)
[tex] y=\sqrt{x+3} [/tex]
[tex] x+3\geq 0 [/tex]
subtracting 3 from both sides
[tex] x\geq -3 [/tex]
x:x∈[-3,∞)
Firstly we have to determine the domain of the function [tex] y=\sqrt{x} [/tex]
The domain of the function is the set of values for which the function is real and defined.
In the function [tex] y=\sqrt{x} [/tex] we can clearly observe that for the negative values of x , the value of y will not be real.
So, the domain for this function is [tex] [0,\infty ) [/tex] or [tex] x\geq 0 [/tex].
The second function is [tex] y=\sqrt{(x+3)} [/tex]
In this function we can clearly observe that for the values of x less than -3, the function is not real.
So, the domain for this function is [tex] [-3,\infty ) [/tex] or [tex] x\geq -3 [/tex]
