Parallelogram FGHI on the coordinate plane below represents the drawing of a horse trail through a local park:

Quadrilateral FGHI is shown on the coordinate plane with coordinates F at −6, −1; G at −1, −1; H at −2, −4; and I −7, −4. Point A is at 3, 8 and point D is at 1, 2.

In order to build a scale model of the trail, the drawing is enlarged as parallelogram ABCD on the coordinate plane. If two corners of the trail are at point A (3, 8) and point D (1, 2), what is another point that could represent point B?

(10, 8)
(13, 8)
(8, 8)
(6, 8)

Parallelogram FGHI on the coordinate plane below represents the drawing of a horse trail through a local park Quadrilateral FGHI is shown on the coordinate plan class=

Respuesta :

we know that

 Parallelogram is a quadrilateral with opposite sides parallel and equal in length


so

[tex]FI=GH\\FG=IH[/tex]

[tex]AD=BC\\AB=DC[/tex]

we have

[tex]F(-6,-1) \\G(-1,-1)\\H(-2,-4)\\I(-7,-4)\\A(3,8)\\D(1,2)[/tex]

Step 1

Find the distance FI


we know that

the distance between two points is equal to the formula

[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]

[tex]F(-6,-1) \\I(-7,-4)[/tex]

substitute the values

[tex]d=\sqrt{(-4+1)^{2}+(-7+6)^{2}}[/tex]

[tex]d=\sqrt{(-3)^{2}+(-1)^{2}}[/tex]

[tex]dFI=\sqrt{10}\ units[/tex]

Step 2

Find the distance FG


we know that

the distance between two points is equal to the formula

[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]

[tex]F(-6,-1) \\G(-1,-1)[/tex]

substitute the values

[tex]d=\sqrt{(-1+1)^{2}+(-1+6)^{2}}[/tex]

[tex]d=\sqrt{(0)^{2}+(5)^{2}}[/tex]

[tex]dFG=5\ units[/tex]

Step 3

Find the distance AD


we know that

the distance between two points is equal to the formula

[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]

[tex]A(3,8)\\D(1,2)[/tex]

substitute the values

[tex]d=\sqrt{(2-8)^{2}+(1-3)^{2}}[/tex]

[tex]d=\sqrt{(-6)^{2}+(-2)^{2}}[/tex]

[tex]dAD=\sqrt{40}\ units[/tex]

Step 4

Find the scale factor

we know that

the scale factor is equal to

[tex]scale\ factor=\frac{dAD}{dFI}[/tex]

we have

[tex]dFI=\sqrt{10}\ units[/tex]

[tex]dAD=\sqrt{40}\ units[/tex]

substitute the values

[tex]scale\ factor=\frac{\sqrt{40}}{\sqrt{10}}=2[/tex]

Step 5

Find the coordinate of point B

we know that

the length side of the segment AB is equal to

[tex]dAB=scale\ factor*dFG[/tex]

we have

[tex]scale\ factor=2[/tex]

[tex]dFG=5\ units[/tex]

substitutes

[tex]dAB=2*5=10\ units[/tex]

the x-coordinate of point B is equal to the x-coordinate of point A plus the distance AB

[tex]Bx=Ax+dAB[/tex]

where

Bx------> is the x-coordinate of point B

Ax-------> is the x-coordinate of point A

dAB------> distance AB

susbtitute

[tex]Bx=3+10=13[/tex]

the y-coordinate of point B is equal to the y-coordinate of point A

[tex]By=8[/tex]

therefore

the coordinate of point B is [tex](13,8)[/tex]

the answer is the option

[tex](13,8)[/tex]

Answer:

13,8

Step-by-step explanation:

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