we are given
first term is
[tex] a_1=42 [/tex]
common ratio is
[tex] r=\frac{3}{4} [/tex]
now, we can find nth term
[tex] a_i=a_1(r)^{i-1} [/tex]
now, we can plug values
[tex] a_i=42(\frac{3}{4})^{i-1} [/tex]
now, we can write in sigma form
[tex] sum=\sum _{i=1}^{\infty }\:42(\frac{3}{4})^{i-1} [/tex]
now, we can find sum
we can use formula
[tex] sum=\frac{a}{1-r} [/tex]
now, we can plug values
we get
[tex] sum=\frac{42}{1-\frac{3}{4}} [/tex]
[tex] sum=168 [/tex]
so, option-D.................Answer