As per the problem we have
A collector has 120 movie posters and 100 band posters.
she wants to sell 24 movie posters.
but still have her poster collection maintain the same ratio of 120/100.
Let she sell x band posters then we have
[tex] \frac{24}{x} =\frac{120}{100} \\
\\
\text{Now simplify we get}\\
\\
x=\frac{100}{120}*24\\
\\
x= \frac{100}{5}\\
\\
x=20\\
\\
\text{She should sell 20 band posters}\\ [/tex]
The answer is 20 bandposters.
As per the problem we have
A collector has 120 movie posters and 100 band posters.
she wants to sell 24 movie posters.
but still have her poster collection maintain the same ratio of 120/100.
