Answer: -
Volume of NaOH = 461 mL = 461/1000 = 0.461 L
pH = 10.0
Using the relation pH + pOH = 14.00
pOH = 14.00 - 10.00= 4.00
Using the relation
[OH⁻] = [tex] 10^{-pOH} [/tex]
= [tex] 10^{-4.00} [/tex] M
Since NaOH is a monobasic acid,
[NaOH] = [OH⁻] = [tex] 10^{-4.00} [/tex] M
Amount of NaOH = [NaOH] x Volume of NaOH
= [tex] 10^{-4.00} [/tex] M x 0.461 L
= 4.61 x 10⁻⁵ mol
Molar mass of NaOH = 23 x 1 + 16 x 1 + 1 x1
= 40 g / mol
Mass of NaOH required = 4.61 x 10⁻⁵ mol x 40 g/ mol
= 1.84 x 10⁻³ g
The study of chemicals and bonds is called chemistry. There are different types of elements and these are metal and nonmetals.
The correct answer is [tex]1.84*10^-{3}[/tex]
The data is given as follows:-
Using the relation pH + pOH = 14.00
pOH = 14.00 - 10.00= 4.00
Using the relation
[OH⁻] = [tex]10^{-poh}\\[/tex]
[tex]10^{-4}[/tex]= M
Since NaOH is a monobasic acid,
[NaOH] = [OH⁻] = [tex]10^{-4}[/tex] M
Amount of NaOH = [NaOH] x Volume of NaOH
= [tex]10^{-4}[/tex] M x 0.461 L
= [tex]4.61 * 10^{-5}[/tex]mol
The molar mass of NaOH = [tex]23 * 1 + 16 * 1 + 1 *1 = 40 g / mol[/tex]
Mass of NaOH required =[tex]4.61 * 10^{-5}mol * 40 g/ mol[/tex]
= 1.84 x 10⁻³ g
Hence, the correct answer is 1.84 x 10⁻³ g.
For more information about the ph, refer to the link:-
https://brainly.com/question/7932885
