Respuesta :

we are given

[tex] log(x)=-2 [/tex]

we know that

whenever nothing is given in base

we will assume base =10

[tex] log_1_0(x)=-2 [/tex]

so, we can solve for x

we can take exponent 10 on both sides

[tex] 10^{log_1_0(x)}=10^{-2} [/tex]

now, log will be cancelled with 10

we get

[tex] x=10^{-2} [/tex]

[tex] x=0.01 [/tex]..............Answer

we are given

log(x)=-2

we know that

whenever nothing is given in base

we will assume base =10

log_1_0(x)=-2

so, we can solve for x

we can take exponent 10 on both sides

10^{log_1_0(x)}=10^{-2}

now, log will be cancelled with 10

we get

x=10^{-2}

x=0.01 ..............Answer

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