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A solution was formed by combining 25.0 g of solid a with 60.0 ml of distilled water, with the water initially at 21.4 °c. the final temperature of the solution was 25.3 °c. calculate the heat released as the solid dissolved, qsoln, assuming no heat loss to the calorimeter (see equation 1).

Respuesta :

We know the heat released or absorbed in a physical process in a calorimeter, H = mass (m)×specific gravity (s)×(change of temperature). Here we can see the change of temperature is (25.3-21.4)=3.9°C. The specific gravity of water (s) is 1 at 25°C. The mass is 25+60=85g. (as density of water is 1g/mL, so 60.0mL water  = 60g of water) The heat released is H = 85×1×3.9 = 331.5 cal.  

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