Respuesta :
The molecular formula of dimethyl sulfoxide is [tex](CH_{3})_{2}SO[/tex]. Molar mass of dimethyl sulfoxide is 78.13 g/mol. Calculate number of moles as follows:
[tex]n=\frac{m}{M}=\frac{7.14\times 10^{3} g}{78.13 g/mol}=91.38 mol[/tex]
From the molecular formula, 1 mole of dimethyl sulfoxide contains 2 moles of Carbon, 6 moles of Hydrogen, 1 mole of Sulfur and 1 mole of oxygen.
Thus, 91.38 moles of dimethyl sulfoxide will have:
Carbon :
[tex]n_{C}=2\times 91.38 moles=182.77 moles[/tex]
Hydrogen:
[tex]n_{H}=6\times 91.38 moles=548.28 moles[/tex]
Sulfur:
[tex]n_{S}=1\times 91.38 moles=91.38 moles[/tex]
Oxygen:
[tex]n_{O}=1\times 91.38 moles=91.38 moles[/tex]
Since, 1 mole of an element equals to [tex]6.023\times 10^{23}[/tex] atoms thus, number of atoms can be calculated as:
Carbon:
[tex]1 mole\rightarrow 6.023\times 10^{23} atoms[/tex]
Thus,
[tex]182.77 moles\rightarrow 182.77\times 6.023\times 10^{23} atoms=1.10\times 10^{26} atoms[/tex]
Hydrogen:
[tex]1 mole\rightarrow 6.023\times 10^{23} atoms[/tex]
Thus,
[tex]548.28 moles\rightarrow 548.28\times 6.023\times 10^{23} atoms=3.30\times 10^{26} atoms[/tex]
Sulfur:
[tex]1 mole\rightarrow 6.023\times 10^{23} atoms[/tex]
Thus,
[tex]91.38 moles\rightarrow 91.38\times 6.023\times 10^{23} atoms=5.50\times 10^{25} atoms[/tex]
Oxygen:
[tex]1 mole\rightarrow 6.023\times 10^{23} atoms[/tex]
Thus,
[tex]91.38 moles\rightarrow 91.38\times 6.023\times 10^{23} atoms=5.50\times 10^{25} atoms[/tex]
Therefore, number of C, S, H and O atoms are [tex]1.10\times 10^{26}, 5.50\times 10^{25}, 3.30\times 10^{26} and 5.50\times 10^{25} atoms[/tex] respectively.
