to better understand the problem see the attached figure
Let
x-------> the length of one rectangle of the enclosed region
y------> the width of one rectangle of the enclosed region
we know that
the dimensions of the enclosed region are
Length=2x
Width=y
the perimeter of one rectangle is equal to
P=2x+2y
in this problem
the perimeter of the enclosed region is equal to
132=[4x+3y]
132=4x+3y------> equation 1
the area of one rectangle is equal to
A=x*y
in this problem
576=[2x*y] ------> equation 2
Solve the system
132=4x+3y------> equation 1
576=[2x*y] ------> equation 2
using a graph tool-------> to solve the system equation
see the attached figure
the solution is
x=24 ft
y=12 ft
therefore
the answer is
the dimensions of the enclosed region are 48 ft * 12 ft
