Respuesta :
Answer:
[tex]9200[/tex] seconds
[tex]2.55[/tex] hours
Explanation:
Given,
Rate of movement of replication fork across the base pair is equal to [tex]500[/tex] base pair per second.
The total number of base pair in the chromosome of an e. coli bacteria [tex]= 4.6[/tex] million
[tex]= 4.6 * 10^6\\[/tex]
Now, time taken by replication fork to replicate the entire e. coli chromosome
is equal to total number of base pairs in the chromosome of an e.coli bacteria divided by the rate of replication
[tex]= \frac{4.6* 10^6}{500} \\= 9200[/tex] seconds
[tex]= \frac{9200}{60*60}\\= 2.55[/tex] hours