P₀ = atmospheric pressure = 101325 Pa
P = pressure at the pipes
h = height of reservoir = 30 m
ρ = density of water = 1000 kg/m³
g = acceleration due gravity = 9.8 m/s²
pressure at the pipes is given as
P = P₀ + ρgh
P = 101325 + (1000) (9.8) (30)
P = 3.95 x 10⁵ Pa
hence the water pressure in the pipes at the bottom is given as
3.95 x 10⁵ Pa
