Respuesta :

Chlidonias

The given expression is [tex]\frac{12500 J}{(106g)(4^{0}C )}[/tex]

This expression denotes the specific heat of a substance which indicates a heat energy of 12500 J is involved in raising the temperature of 106 g of the substance by [tex]4^{0}C[/tex]. Generally, the units of specific heat are [tex]\frac{J}{g.^{0}C }[/tex]

[tex]\frac{12500 J}{(106g)(4^{0}C )}[/tex] = [tex]\frac{12500 J}{(106g)(4^{0}C } = 29.5 \frac{J}{g^{0}C }[/tex]

Therefore,  [tex]\frac{12500 J}{(106g)(4^{0}C )}[/tex] when reduced to one unit will be 29.5 [tex]\frac{J}{g^{0}C }[/tex]

Eduard22sly

Answer:

29.48 J/g°C

Explanation:

Step 1:

Data obtained from the question. This includes:

12500 J/ (106g) (4°C)

From the question given, we were asked to reduce the expression above to a single value

Step 2:

Reduction of the expression.

The reduction of 12500 J/ (106g) (4°C) can be obtained as follow:

12500 J/ (106g) (4°C) = 12500J/424g°C

= 29.48 J/g°C

Therefore, the reduction of 12500 J/ (106g) (4°C) to a single value is 29.48 J/g°C

Otras preguntas