Respuesta :
Answer;
=0.43 m/s²
Solution;
There will be the tension in the cable, T, upwards and the weight of the elevator, mg, downwards.
By Newton's second law, the sum of the forces will be equal to mass×acceleration.
Resultant force = m × a
Then T - mg = ma so the tension in the cable is
T = m(g+a)
The cable will break when T = 21,800 N
Solving for a, that happens when
a = 21800/2130 - g
= 10.23 - g (in m/s^2)
If you're using g = 9.8 m/s^2
Then the maximum acceleration allowed is 10.23-9.8 = 0.43 m/s^2
The maximum upward acceleration can be given to the elevator without breaking it will be 0.4247 m/s².
Given to us
cable supporting = 2130-kg
maximum strength = 2.18×10⁴ N
What maximum upward acceleration can it give the elevator without breaking?
We know that the elevator is moving upward therefore, the tension in the string will be upwards, but since, the lift is moving upward the elevator itself will feel a drag that will be due to the gravity,
thus,
Tension on the string can be written as,
[tex]T = m(a+g)[/tex]
Substitute the values,
[tex]2.18 \times 10^4 = 2130(a+9.81)\\a = 0.4247\rm\ m/s^2[/tex]
Hence, the maximum upward acceleration can be given to the elevator without breaking it will be 0.4247 m/s².
Learn more about Acceleration:
https://brainly.com/question/12134554
