Answer:
There are [tex]1.207\times 10^{24} atoms[/tex] in 80.2 grams of calcium.
Explanation:
Atomic mass of calcium = 40 g/mol
Mass of calcium given = 80.2 g
Moles of calcium = [tex]\frac{80.2 g}{40 g/mol}=2.005 mol[/tex]
1 mol = [tex]N_A=6.022\times 10^{23} [/tex] atoms/ molecules, ions
Number of atoms of calcium in 2.005 moles of calcium:
[tex]2.005 \times 6.022\times 10^{23}=1.207\times 10^{24} atoms[/tex]
There are [tex]1.207\times 10^{24} atoms[/tex] in 80.2 grams of calcium.
