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A rocket ship starts from rest and turns on its forward booster rockets, causing it to have a constant acceleration of 4 m/s^2 rightward. After 3s, what will be the velocity of the rocket ship? Answer using a coordinate system where rightward is positive.

Respuesta :

here rocket starts from rest

It turns the booster and continue with constant acceleration

[tex]a = 4 m/s^2[/tex]

now in order to find the final velocity we can use kinematics equation

[tex]v_f = v_i + at[/tex]

here we know that

[tex]v_i = 0[/tex]

t = 3 s

now plug in all data in above equation

[tex]v_f = 0 + 4*3[/tex]

[tex]v_f = 12 m/s[/tex]

so the rocket will move rightwards with speed 12 m/s after 3 s of boosters

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