Respuesta :
Answer: a) 1.97 grams of carbon disulfide will remain after 37.0 days.
b) 2.85 grams of carbon monosulfide will be formed after 37.0 days.
Explanation: The decomposition of carbon disulfide is given as:
[tex]CS_2(g)\rightarrow CS(g)+S(g)[/tex]
at t=0 4.83g 0 0
at t=37 days 4.83 - x x x
here,
x = amount of [tex]CS_2[/tex] utilised in the reaction
This reaction follows first order kinetics so the rate law equation is:
[tex]k=\frac{2.303}{t}log\frac{A_o}{A}[/tex]
where, k = rate constant
t = time
[tex]A_o[/tex] = Initial mass of reactant
A = Final mass of reactant
a) For this, the value of
[tex]k=2.80\times10^{-7}sec^{-1}[/tex]
t = 370 days = 3196800 sec
[tex]A_o[/tex] = 4.83
A = 4.83-x
Putting values in the above equation, we get
[tex]2.8\times 10^{-7}sec^{-1}=\frac{2.303}{3196800sec}log\left(\frac{4.83}{4.83-x}\right)[/tex]
x = 2.85g
Amount of [tex]CS_2 [/tex] remained after 37 days = 4.83 - x
= 1.97g
b) Amount of carbon monosulfide formed will be equal to "x" only which we have calculated in the previous part.
Amount of carbon monosulfide formed = 2.85g
