Respuesta :
Hello, Your answer is below.
The given equation for the relationship between a planet's orbital period, T and the planet's mean distance from the sun, A is T^2 = A^3. Let the orbital period of planet X be T(X) and that of planet Y = T(Y) and let the mean distance of planet X from the sun be A(X) and that of planet Y = A(Y), then A(Y) = 2A(X) [T(Y)]^2 = [A(Y)]^3 = [2A(X)]^3 But [T(X)]^2 = [A(X)]^3 Thus [T(Y)]^2 = 2^3[T(X)]^2 [T(Y)]^2 / [T(X)]^2 = 2^3 T(Y) / T(X) = 2^3/2 Therefore, the orbital period increased by a factor of 2^3/2.
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Your friend Papaguy.
If the orbital period of planet Y is twice the orbital period of Planet X, by then the factor is the mean distance increased by 4.
Given
The equation T^2 = A^3 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A, in astronomical units, AU.
What is mean value?
The mean is defined as the sum of all data set numbers and the total number in the data set.
If the orbital period of planet Y is twice the orbital period of Planet X,
Therefore,
If the orbital period of planet Y is twice the orbital period of Planet X, by then the factor is the mean distance increased is;
[tex]\rm Factor \of\ increase =\dfrac{2&^3}{2 }\\\\ Factor \of\ increase =4[/tex]
Hence, If the orbital period of planet Y is twice the orbital period of Planet X, by then the factor is the mean distance increased by 4.
To know more about mean value click the link given below.
https://brainly.com/question/12513463
