T= The time it takes for the flower pot to pass the top of my window.
V= The velocity of the flower pot at the moment it is passing the top of my window.
X= The height above the top of my window that the flower pot was dropped.
h = Lw + X
Lw = (1/2)*g*t^2 + V*t
V*t = Lw - (1/2)*g*t^2
V= Lw/t - (1/2)*g*t , On the other hand we know : V=gT.
Therefore we will have: Tg= Lw/t - (1/2)*g*t
T= Lw/(tg) - t/2
Now substitute for T in the following equation: X = (1/2)*g*T^2
X= (1/2)*g*(Lw/(tg) - t/2)^2
Now substitute for X in the very first equation I mentioned: h = Lw + X
h = Lw + (1/2)*g*(Lw/(tg) - t/2)^2
In case you wanted the answer to be simplified, then:
h= (Lw^2)/(2*g*t^2) + (g*t^2)/8 + Lw/2
Answer:
3.26m
Explanation:
Using one of the equation of motion to get the distance of the pot from the window and the ground;
v² = u²+2as where
v is the final velocity = 8m/s
u is the initial velocity = 0m/s
a =+g = acceleration due to gravity (this acceleration is positive since the body is falling downwards)
g = 9.81m/s
s is the distance between the object and the window from which it dropped.
Substituting this values to get the distance s we have;
8² = 0²+2(9.81)s
64 = 19.62s
s = 64/19.62
S = 3.26m
