Respuesta :
4th term = 29
to generate the terms, substitute n = 2, 3, 4 into the rule
noting that b(1) = - 7
b(2) = b(2 - 1) + 12 = b(1) + 12 = -7 + 12 = 5
b(3) = b(3 - 1) + 12 = b(2) + 12 = 5 + 12 = 17
b(4) = b(4 - 1) + 12 = b(3) + 12 = 17 + 12 = 29
Answer: The 4th term in the sequence is 29 .
Step-by-step explanation:
The given recursive formula for the sequence :
[tex]b(1)=-7\\\\ b(n)=b(n-1)+12[/tex]
To find : 4th term
At n=2 , we have
[tex]b(2)=b(1)+12=-7+12=5[/tex] (Second term)
At n=3 , we have
[tex]b(3)=b(2)+12=5+12=17[/tex] (Third term)
At n=4 , we have
[tex]b(4)=b(3)+12=17+12=29[/tex] (Fourth term)
Therefore , the 4th term in the sequence is 29 .