Within the set of whole numbers , one set of numbers satisfies the recursive formula an=(an-1)^2-an-1, when a4=870 what are the first two terms of the sequence?

Respuesta :

Answer: 3 and 6 will be the first and second term of the given series respectively.

Explanation:  since it is given-  [tex]a_n=(a_{n-1} )^2-a_{n-1}[/tex] and [tex]a_4=870[/tex]

so, by replacing n by 4, we will get- [tex]a_4=a_3^2-a_3[/tex]⇒870= [tex]a_3^2-a_3[/tex]⇒ [tex]a_3^2-a_3-870=0[/tex]

after solving this equation we will get, [tex]a_3= -29[/tex] and 30.

If [tex]a_3= -29[/tex], but it is not a whole number.

Thus,[tex]a_3=30[/tex] will be the value of third term of the given series.

Again, by applying the given condition [tex]a_n=(a_{n-1} )^2-a_{n-1}[/tex], [tex]a_2= 6[/tex] or -5 (not possible), so, [tex]a_2=6[/tex] will be the second term.

Similarly, [tex]a_1=3[/tex] or -2 but  we will go to the whole number.

Thus, [tex]a_1=3[/tex] will be the first term.

Answer:

A

Step-by-step explanation: