Respuesta :

gmany

[tex]a_1=-2\\r=-\dfrac{1}{4}\\-------------------\\\\a_{n}=a_{n-1}r\\\\a_2=a_1r\to a_2=-2\left(-\dfrac{1}{4}\right)=\dfrac{1}{2}\\\\a_3=a_2r\to a_3=\left(\dfrac{1}{2}\right)\left(-\dfrac{1}{4}\right)=-\dfrac{1}{8}\\\\a_4=a_3r\to a_4=\left(-\dfrac{1}{8}\right)\left(-\dfrac{1}{4}\right)=\dfrac{1}{32}\\\\\boxed{Answer:\ \dfrac{1}{2},\ -\dfrac{1}{8},\ \dfrac{1}{32}}.[/tex]