Respuesta :
First off sorry it took me so long to respond, had some emergency. Ok now lets get on to the question.
The first box is <3.
The second box is definition of angle bisector.
The third box is <1 .
The fourth box is transitive property of congruence.
The correct answer is ∠1≅∠3 by the transitive property of congruence
How to Prove this Problem?
Given ABCD is parallelogram and DC bisects ∠BDE
To prove ∠1≅∠3
- It is given that ABCD is a parallelogram and So, AB is parallel DC by the definition of parallelogram so ∠1≅∠2 by alternate interior angle theorem
It is also given DC bisects ∠BDE
So, ∠2≅∠3 by definition of angle bisector
Therefore ∠1≅∠3 by the transitive property of congruence
Hence it is proved
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