The equation for what the 2nd number of three consecutive numbers that equal to 414 is : x+(x+1)+(x+2)=414
Multiply and Simplify:
x+x+1+x+2=414
3x+3=414
Subtract 3 from both sides:
3x+3-3=414-3
3x=411
Divide three by both sides to get answer:
3x/3=411/3
x=137.
If you want to check if its correct add the three numbers that come next:
137+138+139=414.
Answer: The 2nd number is 138
Step-by-step explanation:
Let x be the first number, let 2x be the second number and let 3x be the third number
since the sum of the three consecutive numbers is 414, then this implies;
x + 2x + 3x = 414
6x = 414
To get the value of x, we divide both-side of the equation by six(6)
6x / 6 = 414/6
(On the left-hand side of the equation, the six at the numerator will cancel out the six at the denominator leaving us with just x and the right-hand side of the equation, we will simply divide 414 by 6, that will give us 69)
x = 69
The first number is x = 69
The second number is 2x = 2×69 =138
The third number is 3x = 3×69 =207
Adding all these numbers up will result to 414.
That is;
69 + 138 + 207 =414
Therefore the 2nd number is 138
