A soccer ball is kicked At 8m/s. It lands on the ground after being in the air for .85 seconds. At what angle is it kicked?

Respuesta :

If ball remains in air for total time T = 0.85 s

this is also known as time of flight

In order to find the time of flight we can use kinematics

[tex]\Delta Y = v_y*t + \frac{1}{2}at^2[/tex]

so for complete motion its displacement in y direction will be zero

[tex]0 = v_y* 0.85 + \frac{1}{2}(-9.8)(0.85^2)[/tex]

[tex]0 = v_y*0.85 - 3.54[/tex]

[tex]v_y = 4.165 m/s[/tex]

now we know that net velocity of the ball is 8 m/s

while is y direction component we got is vy = 4.165 m/s

now by component method we can say

[tex]v_y = v sin\theta[/tex]

[tex]4.165 = 8 sin\theta[/tex]

[tex]\theta = sin^{-1}\frac{4.165}{8}[/tex]

[tex]\theta = 31.4^0 [/tex]

so it is projected at an angle of 31.4 degree above horizontal