Respuesta :
factor
find wht 2 numbers add to 8 and multiply to 3
none do
use quadratic formula which can be used when
ax^2+bx+c=0
x=[tex] \frac{-b+/- \sqrt{b^{2}}-4ac }{2a} [/tex]
a=1
b=8
c=3
x=[tex] \frac{-8+/- \sqrt{8^{2}-4(1)(3)} }{2(1)} [/tex]
x=[tex] \frac{ -8+/- \sqrt{64-12} }{2} [/tex]
x=[tex] \frac{ -8+/- \sqrt{52} }{2} [/tex]
x=[tex] \frac{ -8+/- 2 \sqrt{13} }{2} [/tex]
x=[tex] -4+/- \sqrt{13} [/tex]
x=[tex] -4+ \sqrt{13} [/tex] or x=[tex] -4- \sqrt{13} [/tex]
aprox x=-7.60555 or x=-0.394449
find wht 2 numbers add to 8 and multiply to 3
none do
use quadratic formula which can be used when
ax^2+bx+c=0
x=[tex] \frac{-b+/- \sqrt{b^{2}}-4ac }{2a} [/tex]
a=1
b=8
c=3
x=[tex] \frac{-8+/- \sqrt{8^{2}-4(1)(3)} }{2(1)} [/tex]
x=[tex] \frac{ -8+/- \sqrt{64-12} }{2} [/tex]
x=[tex] \frac{ -8+/- \sqrt{52} }{2} [/tex]
x=[tex] \frac{ -8+/- 2 \sqrt{13} }{2} [/tex]
x=[tex] -4+/- \sqrt{13} [/tex]
x=[tex] -4+ \sqrt{13} [/tex] or x=[tex] -4- \sqrt{13} [/tex]
aprox x=-7.60555 or x=-0.394449
Use quadratic formula with a=1, b=8, c=3.
x=−b±√b2−4ac2ax=−(8)±√(8)2−4(1)(3)2(1)x=−8±√522x=−4+√13 or x=−4−√13Answer:x=−4+√13 or x=−4−√13I hope that's help !