Ribbon A is 1/3 m long. It is 2/5 m shorter than Ribbon B. What's the total length of the two ribbons?

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CatButAlien CatButAlien · Answer 1 · 2018-12-01T13:47:47+01:00

Hi

Answer:

[tex]\frac{11}{15}[/tex]

Step-by-step explanation:

A = [tex]\frac{1}{3}[/tex]

B = [tex]\frac{2}{5}[/tex]

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A = [tex]\frac{1x5}{3x5}=\frac{5}{15}[/tex]

B = [tex]\frac{2x3}{5x3}=\frac{6}{15}[/tex]

[tex]\frac{5}{15}[/tex] + [tex]\frac{6}{15}[/tex] = [tex]\frac{11}{15}[/tex]

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Good Luck!

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Evadin2019 Evadin2019 · Answer 2 · 2019-10-08T03:52:04+02:00

The total length of the two ribbons is [tex]1\frac{1}{15}[/tex] meters.

Ribbon A = [tex]\frac{1}{3}[/tex] m long

Ribbon A = B -[tex]\frac{2}{5}[/tex] m so B = A + [tex]\frac{2}{5}[/tex] = [tex]\frac{1}{3}[/tex] + [tex]\frac{2}{5}[/tex]

Total Ribbon = A + B

= [tex]\boxed { A + B = \frac{1}{3} + \frac{1}{3} + \frac{2}{5} }\\ \boxed {= \frac{5+5+6}{15} = \frac{16}{15} }\\\boxed {= 1\frac{1}{15} }[/tex]

So the total length of the two ribbons is [tex]1\frac{1}{15}[/tex] meters.

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Keywords: additional fraction, subtraction fraction, mixed fraction, improper fraction