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An onject is.launched from platform. Its height (in meters) x seconds after the launch is modeled by h(x) =-5(x+1)(×-9) How many seconds after launch will the object hit the ground

Respuesta :

wegnerkolmp2741o

Answer:

the object will hit the ground at x=9

Step-by-step explanation:

h(x) =-5(x+1)(×-9)

0 =5(x+1)(×-9)

using the zero product property

the x intercepts or zeros of the equation are x+1 =0  and x-9 =0

x=-1  and x=9

the object will hit the ground at x=9

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