Answer: The reaction quotient [tex]Q_c[/tex] = 0.221.
Explanation:
[tex]Q_c<K_c[/tex] , equilibrium will move in forward direction
[tex]Q_c=K_c[/tex] , equilibrium is attained
[tex]Q_c>K_c[/tex], equilibrium will move in backward direction
Now, according to question
[tex]N_2+3H_2\rightleftharpoons 2NH_3[/tex]
Given:
[tex]K_c[/tex] of the reaction is 0.278 at 800 K
[tex][N_2]=0.411 mol/L ,[H_2]=0.541 mol/L, ,[NH_3]=0.12 mol/L[/tex]
[tex]Q_c=\frac{[NH_3]^2}{[H_2]^3[N_2]}=\frac{0.12\times 0.12}{(0.541)^3\times 0.411}=0.221[/tex]
The reaction quotient [tex]Q_c[/tex] = 0.221.
The value of [tex]Q_c<K_c[/tex] which means that reaction is going in forward direction