contestada

If a coin is thrown with a starting velocity of 0 m/s down a dry well and hits bottom in 1.2 s, what's the depth of the well?

Respuesta :

boffeemadrid

Answer:

[tex]H=7.0632m[/tex]

Step-by-step explanation:

Since, a coin is thrown with velocity "u"=0m/s and time "t"=1.2s,it gains an acceleration due to gravity, then using the formula, [tex]H=ut+\frac{1}{2}gt^{2}[/tex];

Since u=0 and g=9.81, therefore,

[tex]H=\frac{1}{2}(9.81)(1.2)^{2}[/tex]

[tex]H=\frac{1}{2}(9.81)(1.44)[/tex]

[tex]H=\frac{14.1264}{2}[/tex]

[tex]H=7.0632m[/tex]