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Right triangle ABC has three sides with lengths AB= 119, BC = 169, CA= 120. Find the value of cos C. hint: draw and label the triangle. The hypotenuse is always the longest.

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kudzordzifrancis

Answer:

[tex]\cos(C)=\frac{120}{169}[/tex]

Step-by-step explanation:

The triangle is shown in the attachment.

Recall that;

[tex]\cos(C)=\frac{Adjacent}{Hypotenuse}[/tex]

This implies that;

[tex]\cos(C)=\frac{|AC|}{|BC|}[/tex]

We substitute the values into the ratio to obtain

[tex]\cos(C)=\frac{120}{169}[/tex]


Ver imagen kudzordzifrancis

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