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A 0.40 kg soccer ball is kicked so that its incoming velocity of 5 m/s is changed to an outgoing velocity of -25 m/s. What impulse does the player apply to the ball?

Respuesta :

boffeemadrid

Answer:

[tex]{\triangle}p=p_{f}-p_{i}=-10-2=-12kgms^{-1}[/tex]

Step-by-step explanation:

It is given that the mass of the soccer ball is=0.40 kg and it is kicked with the velocity of=[tex]5ms^{-1}[/tex], then the initial momentum will be:

[tex]p_{i}=mv=0.40{\times}5=2kgms^{-1}[/tex]

Then, the velocity is changed to [tex]-25ms^{-1}[/tex], then the final momentum will be:

[tex]p_{f}=mv=0.40{\times}(-25)=-10kgms^{-1}[/tex]

Now, Impulse that the player applied to the ball will be:

[tex]{\triangle}p=p_{f}-p_{i}=-10-2=-12kgms^{-1}[/tex]

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