Answer: [tex]\text{tan a}= \frac{3\sqrt{91} }{91}[/tex]
Step-by-step explanation:
Since, in the triangle abc,
ab = 10√91 unit, bc = 30 unit, ca = 100 unit and m∠b = 90°
⇒ [tex]\text{tan a} = \frac{bc}{ab}[/tex]
⇒ [tex]\text{tan a} = \frac{30}{10\sqrt{91}}[/tex]
⇒ [tex]\text{tan a} =\frac{3}{\sqrt{91}}[/tex]
⇒ [tex]\text{tan a} = \frac{3\times \sqrt{91}}{\sqrt{91}\times \sqrt{91}}[/tex]
⇒ [tex]\text{tan a} = \frac{3\sqrt{91}}{91}[/tex]
Which is the required value of tan(∠a).
