For this case, we must find an equation equivalent to the given equation, but as a function of y.
If we have:
[tex]y = \frac {1} {3} (x + 2)[/tex]
We must clear "x":
[tex]y = \frac {1} {3} x + \frac {2} {3}[/tex]
Subtract [tex]\frac {2} {3}[/tex] from both sides of the equation:
[tex]y- \frac {2} {3} = \frac {1} {3} x + \frac {2} {3} - \frac {2} {3}\\y- \frac {2} {3} = \frac {1} {3} x[/tex]
We multiply by 3 on both sides of the equation:
[tex]3 * (y- \frac {2} {3}) = \frac {1} {3} x * 3\\x = 3 * (y- \frac {2} {3})[/tex]
Thus, an equivalent equation is:
[tex]x = 3 * (y- \frac {2} {3})[/tex]
Answer:
[tex]x = 3 * (y- \frac {2} {3})[/tex]
