Respuesta :

carlosego

Answer: [tex]y=x^{2}+2x-4[/tex]

Step-by-step explanation:

1. To solve the exercise shown, you must expand the equation.

2. Accordind the the square of a sum, you have:

[tex](a+b)^{2}=a^{2}+2ab+b^{2}[/tex]

3. Therefore, you have the equation in standard form:

[tex]y=(x^{2}+2x(1)+1^{2})-5\\y=x^{2}+2x+1-5\\y=x^{2}+2x-4[/tex]

zainebamir540

Answer:

y = x²+2x-4

Step-by-step explanation:

We have given an equation which is in vertex form.

y = (x+1)²-5

We have to convert above equation into standard form.

Standard form of equation is

y = ax²+bx+c

Expanding the square term by using following formula,

(a+b)² = a²+2ab+b²

Now, y = x²+2x+1-5

Adding like terms , we have

y = x²+2x-4 which is the answer.

Otras preguntas