Respuesta :
Answer:
Part 1) There are two real solutions
Part 2) There is one real solution
Part 3) There are no real solutions
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form [tex]ax^{2} +bx+c=0[/tex] is equal to
[tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}[/tex]
If the radicand is positive
[tex](b^{2}-4ac) >0[/tex] ------> There are two real solutions
If the radicand is zero
[tex](b^{2}-4ac) =0[/tex] ------> There is one real solution
If the radicand is negative
[tex](b^{2}-4ac) <0[/tex] ------> There are no real solutions
therefore
Part 1) The radicand is positive
so
There are two real solutions
Part 2) The radicand is equal to zero
so
There is one real solution
Part 3) The radicand is negative
so
There are no real solutions