Answer:
Work done: 0 J
Change in internal energy: +100 J
Explanation:
- The work done by the gas is given by:
[tex]W=p\Delta V[/tex]
where
p is the gas pressure
[tex]\Delta V[/tex] is the change in volume of the gas
Since the gas is kept in a rigid container, its volume is fixed, so there is no change in volume: therefore, [tex]\Delta V=0[/tex] and the work done is zero as well:
[tex]W=0[/tex]
- The change in internal energy of the gas is given by the 1st law of thermodynamics:
[tex]\Delta U=Q-W[/tex]
where Q is the heat supplied to the gas. Since W=0 and Q=+100 J, then the change in internal energy of the gas is
[tex]\Delta U=+100 J+0=+100 J[/tex]
