100 POINTS AND BRAINLIEST
A side of a triangle is divided into three congruent parts. Two lines, parallel to another side of the triangle, are drawn through each dividing point. Find the area of the quadrilaterals formed by those lines if the area of the original triangle is 24.

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frika

Answer:

8 square units and [tex]\frac{40}{3}[/tex] square units

Step-by-step explanation:

The area of the triangle ABC is 24 square units.

1. Triangles ABC and FBG are similar with scale factor [tex]\frac{1}{3},[/tex] then

[tex]\dfrac{A_{\triangle FBG}}{A_{\triangle ABC}}=\dfrac{1}{9}\Rightarrow A_{\triangle FBG}=\dfrac{1}{9}\cdot 24=\dfrac{8}{3}\ un^2.[/tex]

2. Triangles ABC and DBE are similar with scale factor [tex]\frac{2}{3},[/tex] then

[tex]\dfrac{A_{\triangle DBE}}{A_{\triangle ABC}}=\dfrac{4}{9}\Rightarrow A_{\triangle DBE}=\dfrac{4}{9}\cdot 24=\dfrac{32}{3}\ un^2.[/tex]

3. Thus, the area of the quadrilateral DFGE is

[tex]A_{DFGE}=A_{\triangle DBE}-A_{\triangle FBG}=\dfrac{32}{3}-\dfrac{8}{3}=8\ un^2.[/tex]

and the area of the quadrilateral ADEC is

[tex]A_{ADEC}=A_{\triangle ABC}-A_{\triangle DBE}=24-\dfrac{32}{3}=\dfrac{40}{3}\ un^2.[/tex]

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Answer:

8 square units and 40/3 square units

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