What is the equation of the circle with center (-1,-2) and passes through the point (6,4)?

Which of the following points is also located on the circle?
A. (6,-6)
B. (-10,0)
C. (-6,4)

Respuesta :

Answer:

[tex](x+1)^2 + (y+2)^2 = 85[/tex]

and B

Step-by-step explanation:

To write the equation of a circle, use the formula [tex](x-h)^2+(y-k)^2 = r^2[/tex] where the center of the circle is (h, k).

This means the equation is [tex](x--1)^2 + (y--2)^2 = r^2 \\\\ (x+1)^2 + (y+2)^2 = r^2[/tex].

Find the radius r by finding the distance between (-1,-2) and (6,4) using the distance formula.

[tex]d = \sqrt{(6--1)^2 + (4--2)^2} =\sqrt{(7)^2 + (6)^2} =\sqrt{49+36} =\sqrt{85}[/tex]

Since the radius is √85 and therefore [tex]r^2 = 85[/tex].

The equation is [tex](x+1)^2 + (y+2)^2 = 85[/tex].

To see what other point is on the circle, substitute the (x,y) in the equation.

(-10+1)^2 + (0+2)^2 = 85

81 + 4 = 85

85 = 85

The point (-10,0) is on the circle.