The molar volume is the volume occupied by 1 mol of any gas at STP.
The molar volume is 22.4 L
The volume occupied by 1.00 mol is 22.4 L
Therefore the volume occupied by 3.00 mol is - 22.4 L x 3 = 67.2 L
The answer is that 3.00 mol of gas particles occupy a volume of -
D. 67.2 L
Answer:
The volume that 3 moles of gas particles occupy is 67.2 L (option D)
Explanation:
The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.
Then it is possible to apply a rule of three as follows: if according to STP 1 mole is available in 22.4 L, 3 moles in how much volume is it?
[tex]volume=\frac{3 moles*22.4 liters}{1 mole}[/tex]
volume=67.2 L
The volume that 3 moles of gas particles occupy is 67.2 L (option D)
